What is the output of the program ? [based on exception]

1. class SampleExe {
2. void run() throws Exception {
3. System.out.println("run before x");
4. int x = 10 / 0;
5. System.out.println("run after x");
6. }
7. }
8. 
   
9. public class SmapleExe1 {
10. public static void main(String[] args) {
11. SampleExe exe = new SampleExe();
12. exe.run();
13. }
14. }

Output: Unhandled type exception at compile time at line 12
--------------------------------------------------------------------

1. class SampleExe {
2. void run() throws Exception {
3. System.out.println("run before x");
4. int x = 10 / 0;
5. System.out.println("run after x");
6. }
7. }
8. 
   
9. public class SmapleExe1 {
10. public static void main(String[] args) throws Exception {
11. SampleExe exe = new SampleExe();
12. exe.run();
13. }
14. }

Output: 

run before x

java.lang.ArithmeticException: / by zero at line 4

--------------------------------------------------------------------

1. class SampleExe {
2. void run() throws Exception {
3. System.out.println("run before x");
4. int x = 10 / 0;
5. System.out.println("run after x");
6. }
7. }
8. 
   
9. public class SmapleExe1 {
10. public static void main(String[] args) {
11. SampleExe exe = new SampleExe();
12. try {
13. exe.run();
14. } catch (Exception e) {
15. e.printStackTrace();
16. }
17. }
18. }

Output: 

run before x

java.lang.ArithmeticException: / by zero at line 4