Problem statement:
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
import java.util.HashMap;
public class Solutions {
public static void main(String args[]) {
int nums[] = {2, 7, 11, 15};
int target = 9;
int idx[] = twoSum(nums, target);
for (int index : idx) {
System.out.print(index + " ");
}
}
public static int[] twoSum(int nums[], int target) {
HashMap m = new HashMap();
int arr[] = new int[2];
for (int i = 0; i < nums.length; i++) {
Integer val = (Integer) m.get(target - nums[i]);
if (val == null) {
m.put(nums[i], i);
} else {
arr[0] = val;
arr[1] = i;
}
}
return arr;
}
}
Output: [0,1]
Expected: [0,1]
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
import java.util.HashMap;
public class Solutions {
public static void main(String args[]) {
int nums[] = {2, 7, 11, 15};
int target = 9;
int idx[] = twoSum(nums, target);
for (int index : idx) {
System.out.print(index + " ");
}
}
public static int[] twoSum(int nums[], int target) {
HashMap m = new HashMap();
int arr[] = new int[2];
for (int i = 0; i < nums.length; i++) {
Integer val = (Integer) m.get(target - nums[i]);
if (val == null) {
m.put(nums[i], i);
} else {
arr[0] = val;
arr[1] = i;
}
}
return arr;
}
}
Output: [0,1]
Expected: [0,1]
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